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11300321022113 is a prime number
BaseRepresentation
bin1010010001110000111110…
…0111101101000010100001
31111000022002210122022121102
42210130033213231002201
52440121024140201423
640011143521204145
72244264326562344
oct244341747550241
944008083568542
1011300321022113
113667491688942
1213260b2790655
1363c800901176
142b0d1d1a045b
15148e3212ac28
hexa470f9ed0a1

11300321022113 has 2 divisors, whose sum is σ = 11300321022114. Its totient is φ = 11300321022112.

The previous prime is 11300321022101. The next prime is 11300321022161. The reversal of 11300321022113 is 31122012300311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9165586710784 + 2134734311329 = 3027472^2 + 1461073^2 .

It is an emirp because it is prime and its reverse (31122012300311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11300321022113 - 24 = 11300321022097 is a prime.

It is not a weakly prime, because it can be changed into another prime (11300321022173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650160511056 + 5650160511057.

It is an arithmetic number, because the mean of its divisors is an integer number (5650160511057).

Almost surely, 211300321022113 is an apocalyptic number.

It is an amenable number.

11300321022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300321022113 is an equidigital number, since it uses as much as digits as its factorization.

11300321022113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11300321022113 its reverse (31122012300311), we get a palindrome (42422333322424).

The spelling of 11300321022113 in words is "eleven trillion, three hundred billion, three hundred twenty-one million, twenty-two thousand, one hundred thirteen".