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113003242399981 is a prime number
BaseRepresentation
bin11001101100011010011110…
…000111110010100011101101
3112211010000010020222001011101
4121230122132013302203231
5104302421120023244411
61040200550051123101
732542133455646053
oct3154323607624355
9484100106861141
10113003242399981
1133008451389a7a
12108109512a3491
134b09210796c1b
141dc95596dc1d3
15d0e71892c8c1
hex66c69e1f28ed

113003242399981 has 2 divisors, whose sum is σ = 113003242399982. Its totient is φ = 113003242399980.

The previous prime is 113003242399889. The next prime is 113003242400017. The reversal of 113003242399981 is 189993242300311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82330852113225 + 30672390286756 = 9073635^2 + 5538266^2 .

It is a cyclic number.

It is not a de Polignac number, because 113003242399981 - 213 = 113003242391789 is a prime.

It is a super-2 number, since 2×1130032423999812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113003242399081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56501621199990 + 56501621199991.

It is an arithmetic number, because the mean of its divisors is an integer number (56501621199991).

Almost surely, 2113003242399981 is an apocalyptic number.

It is an amenable number.

113003242399981 is a deficient number, since it is larger than the sum of its proper divisors (1).

113003242399981 is an equidigital number, since it uses as much as digits as its factorization.

113003242399981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2519424, while the sum is 55.

The spelling of 113003242399981 in words is "one hundred thirteen trillion, three billion, two hundred forty-two million, three hundred ninety-nine thousand, nine hundred eighty-one".