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113004032021 is a prime number
BaseRepresentation
bin110100100111110010…
…0001011000000010101
3101210200110000121121022
41221033210023000111
53322413013011041
6123525140330525
711110226265206
oct1511744130025
9353613017538
10113004032021
1143a19914901
1219a989a3a45
13a86b99374a
1456801595ad
152e15bd624b
hex1a4f90b015

113004032021 has 2 divisors, whose sum is σ = 113004032022. Its totient is φ = 113004032020.

The previous prime is 113004031993. The next prime is 113004032083. The reversal of 113004032021 is 120230400311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58327563121 + 54676468900 = 241511^2 + 233830^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113004032021 is a prime.

It is a super-2 number, since 2×1130040320212 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113004032321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56502016010 + 56502016011.

It is an arithmetic number, because the mean of its divisors is an integer number (56502016011).

Almost surely, 2113004032021 is an apocalyptic number.

It is an amenable number.

113004032021 is a deficient number, since it is larger than the sum of its proper divisors (1).

113004032021 is an equidigital number, since it uses as much as digits as its factorization.

113004032021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 113004032021 its reverse (120230400311), we get a palindrome (233234432332).

The spelling of 113004032021 in words is "one hundred thirteen billion, four million, thirty-two thousand, twenty-one".