Base | Representation |
---|---|
bin | 10101000011000111… |
… | …00111101110010111 |
3 | 1002011112201000012220 |
4 | 22201203213232113 |
5 | 141120400412434 |
6 | 5105154513423 |
7 | 550014564414 |
oct | 124143475627 |
9 | 32145630186 |
10 | 11300404119 |
11 | 4879868964 |
12 | 2234595873 |
13 | 10b1237374 |
14 | 792b4b10b |
15 | 46212cd49 |
hex | 2a18e7b97 |
11300404119 has 4 divisors (see below), whose sum is σ = 15067205496. Its totient is φ = 7533602744.
The previous prime is 11300404111. The next prime is 11300404127. The reversal of 11300404119 is 91140400311.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11300404111) and next prime (11300404127).
It is a cyclic number.
It is not a de Polignac number, because 11300404119 - 23 = 11300404111 is a prime.
It is a super-2 number, since 2×113004041192 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11300404111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883400684 + ... + 1883400689.
It is an arithmetic number, because the mean of its divisors is an integer number (3766801374).
Almost surely, 211300404119 is an apocalyptic number.
11300404119 is a deficient number, since it is larger than the sum of its proper divisors (3766801377).
11300404119 is an equidigital number, since it uses as much as digits as its factorization.
11300404119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3766801376.
The product of its (nonzero) digits is 432, while the sum is 24.
The spelling of 11300404119 in words is "eleven billion, three hundred million, four hundred four thousand, one hundred nineteen".
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