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113004133030 = 2511300413303
BaseRepresentation
bin110100100111110010…
…0100011101010100110
3101210200110012202011101
41221033210203222212
53322413024224110
6123525142430314
711110230165535
oct1511744435246
9353613182141
10113004133030
1143a19983788
1219a98a3239a
13a86b9ca709
14568018431c
152e15c0613a
hex1a4f923aa6

113004133030 has 8 divisors (see below), whose sum is σ = 203407439472. Its totient is φ = 45201653208.

The previous prime is 113004133019. The next prime is 113004133049. The reversal of 113004133030 is 30331400311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 113004132989 and 113004133007.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5650206642 + ... + 5650206661.

It is an arithmetic number, because the mean of its divisors is an integer number (25425929934).

Almost surely, 2113004133030 is an apocalyptic number.

113004133030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113004133030 is a deficient number, since it is larger than the sum of its proper divisors (90403306442).

113004133030 is a wasteful number, since it uses less digits than its factorization.

113004133030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11300413310.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 113004133030 its reverse (30331400311), we get a palindrome (143335533341).

The spelling of 113004133030 in words is "one hundred thirteen billion, four million, one hundred thirty-three thousand, thirty".

Divisors: 1 2 5 10 11300413303 22600826606 56502066515 113004133030