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1130043199993 is a prime number
BaseRepresentation
bin10000011100011011110…
…100101101000111111001
311000000211122122110100121
4100130123310231013321
5122003312024344433
62223045031333241
7144433344466621
oct20343364550771
94000748573317
101130043199993
113a6280a208a4
12163015221221
13827410b75a6
143c9a1559881
151e5dd2aec2d
hex1071bd2d1f9

1130043199993 has 2 divisors, whose sum is σ = 1130043199994. Its totient is φ = 1130043199992.

The previous prime is 1130043199991. The next prime is 1130043200047. The reversal of 1130043199993 is 3999913400311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 868648232169 + 261394967824 = 932013^2 + 511268^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130043199993 - 21 = 1130043199991 is a prime.

Together with 1130043199991, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1130043199993.

It is not a weakly prime, because it can be changed into another prime (1130043199991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565021599996 + 565021599997.

It is an arithmetic number, because the mean of its divisors is an integer number (565021599997).

Almost surely, 21130043199993 is an apocalyptic number.

It is an amenable number.

1130043199993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130043199993 is an equidigital number, since it uses as much as digits as its factorization.

1130043199993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 708588, while the sum is 52.

The spelling of 1130043199993 in words is "one trillion, one hundred thirty billion, forty-three million, one hundred ninety-nine thousand, nine hundred ninety-three".