Base | Representation |
---|---|
bin | 110100100111110010… |
… | …1010011110111010011 |
3 | 101210200110120202222021 |
4 | 1221033211103313103 |
5 | 3322413102033301 |
6 | 123525150552311 |
7 | 11110231650235 |
oct | 1511745236723 |
9 | 353613522867 |
10 | 113004330451 |
11 | 43a19aa9041 |
12 | 19a98b08697 |
13 | a86ba6952c |
14 | 56801d6255 |
15 | 2e15c448a1 |
hex | 1a4f953dd3 |
113004330451 has 2 divisors, whose sum is σ = 113004330452. Its totient is φ = 113004330450.
The previous prime is 113004330391. The next prime is 113004330557. The reversal of 113004330451 is 154033400311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113004330451 - 225 = 112970776019 is a prime.
It is not a weakly prime, because it can be changed into another prime (113004330851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56502165225 + 56502165226.
It is an arithmetic number, because the mean of its divisors is an integer number (56502165226).
Almost surely, 2113004330451 is an apocalyptic number.
113004330451 is a deficient number, since it is larger than the sum of its proper divisors (1).
113004330451 is an equidigital number, since it uses as much as digits as its factorization.
113004330451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 113004330451 its reverse (154033400311), we get a palindrome (267037730762).
The spelling of 113004330451 in words is "one hundred thirteen billion, four million, three hundred thirty thousand, four hundred fifty-one".
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