Base | Representation |
---|---|
bin | 110100100111110010… |
… | …1100111110011100101 |
3 | 101210200110201221000112 |
4 | 1221033211213303211 |
5 | 3322413112142013 |
6 | 123525152422405 |
7 | 11110232440334 |
oct | 1511745476345 |
9 | 353613657015 |
10 | 113004412133 |
11 | 43a1a054448 |
12 | 19a98b47a05 |
13 | a86ba97772 |
14 | 5680217d1b |
15 | 2e15c5dba8 |
hex | 1a4f967ce5 |
113004412133 has 2 divisors, whose sum is σ = 113004412134. Its totient is φ = 113004412132.
The previous prime is 113004412067. The next prime is 113004412159. The reversal of 113004412133 is 331214400311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113002200964 + 2211169 = 336158^2 + 1487^2 .
It is an emirp because it is prime and its reverse (331214400311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113004412133 - 224 = 112987634917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113004412099 and 113004412108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113004412333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56502206066 + 56502206067.
It is an arithmetic number, because the mean of its divisors is an integer number (56502206067).
Almost surely, 2113004412133 is an apocalyptic number.
It is an amenable number.
113004412133 is a deficient number, since it is larger than the sum of its proper divisors (1).
113004412133 is an equidigital number, since it uses as much as digits as its factorization.
113004412133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 113004412133 its reverse (331214400311), we get a palindrome (444218812444).
The spelling of 113004412133 in words is "one hundred thirteen billion, four million, four hundred twelve thousand, one hundred thirty-three".
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