1130044331231 has 2 divisors, whose sum is σ = 1130044331232. Its totient is φ = 1130044331230.

The previous prime is 1130044331203. The next prime is 1130044331237. The reversal of 1130044331231 is 1321334400311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130044331231 is a prime.

It is a super-2 number, since 2×1130044331231² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1130044331231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130044331237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565022165615 + 565022165616.

It is an arithmetic number, because the mean of its divisors is an integer number (565022165616).

Almost surely, 2^{1130044331231} is an apocalyptic number.

1130044331231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130044331231 is an equidigital number, since it uses as much as digits as its factorization.

1130044331231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1130044331231 its reverse (1321334400311), we get a palindrome (2451378731542).

The spelling of 1130044331231 in words is "one trillion, one hundred thirty billion, forty-four million, three hundred thirty-one thousand, two hundred thirty-one".