Base | Representation |
---|---|
bin | 110100100111111101… |
… | …1010100100000011101 |
3 | 101210200212102220122122 |
4 | 1221033323110200131 |
5 | 3322421041202003 |
6 | 123525514352325 |
7 | 11110332000641 |
oct | 1511773244035 |
9 | 353625386578 |
10 | 113010100253 |
11 | 43a22289a76 |
12 | 19a9aa2b6a5 |
13 | a87000980b |
14 | 5680c98c21 |
15 | 2e164d4238 |
hex | 1a4fed481d |
113010100253 has 2 divisors, whose sum is σ = 113010100254. Its totient is φ = 113010100252.
The previous prime is 113010100213. The next prime is 113010100277. The reversal of 113010100253 is 352001010311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112572328324 + 437771929 = 335518^2 + 20923^2 .
It is a cyclic number.
It is not a de Polignac number, because 113010100253 - 210 = 113010099229 is a prime.
It is a super-2 number, since 2×1130101002532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113010100213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505050126 + 56505050127.
It is an arithmetic number, because the mean of its divisors is an integer number (56505050127).
Almost surely, 2113010100253 is an apocalyptic number.
It is an amenable number.
113010100253 is a deficient number, since it is larger than the sum of its proper divisors (1).
113010100253 is an equidigital number, since it uses as much as digits as its factorization.
113010100253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 113010100253 its reverse (352001010311), we get a palindrome (465011110564).
The spelling of 113010100253 in words is "one hundred thirteen billion, ten million, one hundred thousand, two hundred fifty-three".
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