Base | Representation |
---|---|
bin | 11001101100100000111000… |
… | …101110001001010000000001 |
3 | 112211010122220100021220212011 |
4 | 121230200320232021100001 |
5 | 104303024222031103321 |
6 | 1040204045412132521 |
7 | 32542466254023265 |
oct | 3154407056112001 |
9 | 484118810256764 |
10 | 113010131112961 |
11 | 33010366932aa5 |
12 | 10812154307141 |
13 | 4b09a6aa06a54 |
14 | 1dc9a1056a0a5 |
15 | d0e9bd5b2ae1 |
hex | 66c838b89401 |
113010131112961 has 2 divisors, whose sum is σ = 113010131112962. Its totient is φ = 113010131112960.
The previous prime is 113010131112881. The next prime is 113010131113037. The reversal of 113010131112961 is 169211131010311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99909640421361 + 13100490691600 = 9995481^2 + 3619460^2 .
It is a cyclic number.
It is not a de Polignac number, because 113010131112961 - 219 = 113010130588673 is a prime.
It is not a weakly prime, because it can be changed into another prime (113010131112161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505065556480 + 56505065556481.
It is an arithmetic number, because the mean of its divisors is an integer number (56505065556481).
Almost surely, 2113010131112961 is an apocalyptic number.
It is an amenable number.
113010131112961 is a deficient number, since it is larger than the sum of its proper divisors (1).
113010131112961 is an equidigital number, since it uses as much as digits as its factorization.
113010131112961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 31.
The spelling of 113010131112961 in words is "one hundred thirteen trillion, ten billion, one hundred thirty-one million, one hundred twelve thousand, nine hundred sixty-one".
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