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113010134197 is a prime number
BaseRepresentation
bin110100100111111101…
…1011100110010110101
3101210200212111122012211
41221033323130302311
53322421043243242
6123525515213421
711110332201622
oct1511773346265
9353625448184
10113010134197
1143a22302524
1219a9aa47271
13a87001c0bc
145680ca7349
152e164de317
hex1a4fedccb5

113010134197 has 2 divisors, whose sum is σ = 113010134198. Its totient is φ = 113010134196.

The previous prime is 113010134141. The next prime is 113010134203. The reversal of 113010134197 is 791431010311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68724719716 + 44285414481 = 262154^2 + 210441^2 .

It is an emirp because it is prime and its reverse (791431010311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113010134197 - 211 = 113010132149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113010137197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505067098 + 56505067099.

It is an arithmetic number, because the mean of its divisors is an integer number (56505067099).

Almost surely, 2113010134197 is an apocalyptic number.

It is an amenable number.

113010134197 is a deficient number, since it is larger than the sum of its proper divisors (1).

113010134197 is an equidigital number, since it uses as much as digits as its factorization.

113010134197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 31.

The spelling of 113010134197 in words is "one hundred thirteen billion, ten million, one hundred thirty-four thousand, one hundred ninety-seven".