Base | Representation |
---|---|
bin | 11001101100100001101101… |
… | …010010101010000111110111 |
3 | 112211010202011210220111122122 |
4 | 121230201231102222013313 |
5 | 104303033023323200043 |
6 | 1040204313120150155 |
7 | 32542530153550163 |
oct | 3154415522520767 |
9 | 484122153814578 |
10 | 113011013100023 |
11 | 33010779781a25 |
12 | 1081235b76835b |
13 | 4b09b7b66459c |
14 | 1dc9a95757ca3 |
15 | d0ea20c32368 |
hex | 66c86d4aa1f7 |
113011013100023 has 2 divisors, whose sum is σ = 113011013100024. Its totient is φ = 113011013100022.
The previous prime is 113011013100001. The next prime is 113011013100047. The reversal of 113011013100023 is 320001310110311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113011013100023 - 28 = 113011013099767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113011013099974 and 113011013100010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113011013100053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505506550011 + 56505506550012.
It is an arithmetic number, because the mean of its divisors is an integer number (56505506550012).
Almost surely, 2113011013100023 is an apocalyptic number.
113011013100023 is a deficient number, since it is larger than the sum of its proper divisors (1).
113011013100023 is an equidigital number, since it uses as much as digits as its factorization.
113011013100023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113011013100023 its reverse (320001310110311), we get a palindrome (433012323210334).
The spelling of 113011013100023 in words is "one hundred thirteen trillion, eleven billion, thirteen million, one hundred thousand, twenty-three".
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