Base | Representation |
---|---|
bin | 1010010001110011111111… |
… | …1101011101010010010111 |
3 | 1111000101012022200211211022 |
4 | 2210130333331131102113 |
5 | 2440124204244444002 |
6 | 40011400212031355 |
7 | 2244323405210201 |
oct | 244347775352227 |
9 | 44011168624738 |
10 | 11301132031127 |
11 | 3667868458a24 |
12 | 132629a30255b |
13 | 63c8cc939c63 |
14 | 2b0d98b93771 |
15 | 148e7d429ba2 |
hex | a473ff5d497 |
11301132031127 has 2 divisors, whose sum is σ = 11301132031128. Its totient is φ = 11301132031126.
The previous prime is 11301132031103. The next prime is 11301132031139. The reversal of 11301132031127 is 72113023110311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11301132031127 - 238 = 11026254124183 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11301132031096 and 11301132031105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301132331127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650566015563 + 5650566015564.
It is an arithmetic number, because the mean of its divisors is an integer number (5650566015564).
Almost surely, 211301132031127 is an apocalyptic number.
11301132031127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301132031127 is an equidigital number, since it uses as much as digits as its factorization.
11301132031127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 26.
Adding to 11301132031127 its reverse (72113023110311), we get a palindrome (83414155141438).
The spelling of 11301132031127 in words is "eleven trillion, three hundred one billion, one hundred thirty-two million, thirty-one thousand, one hundred twenty-seven".
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