Base | Representation |
---|---|
bin | 110100101000000000… |
… | …0000001000011100100 |
3 | 101210200221202110022222 |
4 | 1221100000001003210 |
5 | 3322421400100200 |
6 | 123530001011512 |
7 | 11110345316000 |
oct | 1512000010344 |
9 | 353627673288 |
10 | 113011331300 |
11 | 43a22a4a96a |
12 | 19a9b323b98 |
13 | a87034ac4a |
14 | 56810d9700 |
15 | 2e16678d85 |
hex | 1a500010e4 |
113011331300 has 72 divisors (see below), whose sum is σ = 285987945600. Its totient is φ = 38746730400.
The previous prime is 113011331297. The next prime is 113011331357. The reversal of 113011331300 is 3133110311.
It is a super-3 number, since 3×1130113313003 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1613096 + ... + 1681695.
It is an arithmetic number, because the mean of its divisors is an integer number (3972054800).
Almost surely, 2113011331300 is an apocalyptic number.
113011331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113011331300 is an abundant number, since it is smaller than the sum of its proper divisors (172976614300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113011331300 is a wasteful number, since it uses less digits than its factorization.
113011331300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3294826 (or 3294805 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 113011331300 its reverse (3133110311), we get a palindrome (116144441611).
The spelling of 113011331300 in words is "one hundred thirteen billion, eleven million, three hundred thirty-one thousand, three hundred".
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