Base | Representation |
---|---|
bin | 10101000011001110… |
… | …00010111011101101 |
3 | 1002011121101121212122 |
4 | 22201213002323231 |
5 | 141121113130442 |
6 | 5105230042325 |
7 | 550025324216 |
oct | 124147027355 |
9 | 32147347778 |
10 | 11301301997 |
11 | 487a321507 |
12 | 22349493a5 |
13 | 10b148cc5b |
14 | 792d0240d |
15 | 462258dd2 |
hex | 2a19c2eed |
11301301997 has 2 divisors, whose sum is σ = 11301301998. Its totient is φ = 11301301996.
The previous prime is 11301301987. The next prime is 11301302063. The reversal of 11301301997 is 79910310311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7421133316 + 3880168681 = 86146^2 + 62291^2 .
It is a cyclic number.
It is not a de Polignac number, because 11301301997 - 24 = 11301301981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11301301967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650650998 + 5650650999.
It is an arithmetic number, because the mean of its divisors is an integer number (5650650999).
Almost surely, 211301301997 is an apocalyptic number.
It is an amenable number.
11301301997 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301301997 is an equidigital number, since it uses as much as digits as its factorization.
11301301997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 35.
The spelling of 11301301997 in words is "eleven billion, three hundred one million, three hundred one thousand, nine hundred ninety-seven".
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