Base | Representation |
---|---|
bin | 1010010001110100101010… |
… | …1100011101000010100011 |
3 | 1111000101122212120110111021 |
4 | 2210131022230131002203 |
5 | 2440130041400414133 |
6 | 40011430124030311 |
7 | 2244331023030415 |
oct | 244351254350243 |
9 | 44011585513437 |
10 | 11301312123043 |
11 | 3667950083718 |
12 | 132632a692397 |
13 | 63c92b043917 |
14 | 2b0db4a729b5 |
15 | 148e8e15052d |
hex | a474ab1d0a3 |
11301312123043 has 2 divisors, whose sum is σ = 11301312123044. Its totient is φ = 11301312123042.
The previous prime is 11301312122999. The next prime is 11301312123097. The reversal of 11301312123043 is 34032121310311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11301312123043 - 221 = 11301310025891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11301312122999 and 11301312123017.
It is not a weakly prime, because it can be changed into another prime (11301312123443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650656061521 + 5650656061522.
It is an arithmetic number, because the mean of its divisors is an integer number (5650656061522).
Almost surely, 211301312123043 is an apocalyptic number.
11301312123043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301312123043 is an equidigital number, since it uses as much as digits as its factorization.
11301312123043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11301312123043 its reverse (34032121310311), we get a palindrome (45333433433354).
The spelling of 11301312123043 in words is "eleven trillion, three hundred one billion, three hundred twelve million, one hundred twenty-three thousand, forty-three".
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