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11301312222127 is a prime number
BaseRepresentation
bin1010010001110100101010…
…1100110101001110101111
31111000101122212202111102001
42210131022230311032233
52440130041412102002
640011430130113131
72244331023622324
oct244351254651657
944011585674361
1011301312222127
113667950141104
12132632a71b7a7
1363c92b079a55
142b0db4a9ab4b
15148e8e16ea87
hexa474ab353af

11301312222127 has 2 divisors, whose sum is σ = 11301312222128. Its totient is φ = 11301312222126.

The previous prime is 11301312222091. The next prime is 11301312222131. The reversal of 11301312222127 is 72122221310311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11301312222127 - 231 = 11299164738479 is a prime.

It is a super-2 number, since 2×113013122221272 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11301312222095 and 11301312222104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11301312222157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650656111063 + 5650656111064.

It is an arithmetic number, because the mean of its divisors is an integer number (5650656111064).

Almost surely, 211301312222127 is an apocalyptic number.

11301312222127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11301312222127 is an equidigital number, since it uses as much as digits as its factorization.

11301312222127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 11301312222127 its reverse (72122221310311), we get a palindrome (83423533532438).

The spelling of 11301312222127 in words is "eleven trillion, three hundred one billion, three hundred twelve million, two hundred twenty-two thousand, one hundred twenty-seven".