Base | Representation |
---|---|
bin | 10101000011001110… |
… | …01111101010010011 |
3 | 1002011121111021101112 |
4 | 22201213033222103 |
5 | 141121121313011 |
6 | 5105231123535 |
7 | 550025632214 |
oct | 124147175223 |
9 | 32147437345 |
10 | 11301354131 |
11 | 487a3576a1 |
12 | 22349735ab |
13 | 10b14aa8c2 |
14 | 792d1740b |
15 | 46226958b |
hex | 2a19cfa93 |
11301354131 has 2 divisors, whose sum is σ = 11301354132. Its totient is φ = 11301354130.
The previous prime is 11301354107. The next prime is 11301354133. The reversal of 11301354131 is 13145310311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11301354131 - 26 = 11301354067 is a prime.
It is a super-2 number, since 2×113013541312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 11301354133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11301354097 and 11301354106.
It is not a weakly prime, because it can be changed into another prime (11301354133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650677065 + 5650677066.
It is an arithmetic number, because the mean of its divisors is an integer number (5650677066).
Almost surely, 211301354131 is an apocalyptic number.
11301354131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301354131 is an equidigital number, since it uses as much as digits as its factorization.
11301354131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 11301354131 its reverse (13145310311), we get a palindrome (24446664442).
The spelling of 11301354131 in words is "eleven billion, three hundred one million, three hundred fifty-four thousand, one hundred thirty-one".
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