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1130202013 is a prime number
BaseRepresentation
bin100001101011101…
…1000001110011101
32220202200012200211
41003113120032131
54303312431023
6304052052421
740002362413
oct10327301635
92822605624
101130202013
1152aa73556
12276604111
131501c68b5
14aa1612b3
156934ea0d
hex435d839d

1130202013 has 2 divisors, whose sum is σ = 1130202014. Its totient is φ = 1130202012.

The previous prime is 1130202001. The next prime is 1130202071. The reversal of 1130202013 is 3102020311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 961124004 + 169078009 = 31002^2 + 13003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130202013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130201984 and 1130202002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130202113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565101006 + 565101007.

It is an arithmetic number, because the mean of its divisors is an integer number (565101007).

Almost surely, 21130202013 is an apocalyptic number.

It is an amenable number.

1130202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130202013 is an equidigital number, since it uses as much as digits as its factorization.

1130202013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1130202013 is about 33618.4772558187. The cubic root of 1130202013 is about 1041.6425022775.

Adding to 1130202013 its reverse (3102020311), we get a palindrome (4232222324).

The spelling of 1130202013 in words is "one billion, one hundred thirty million, two hundred two thousand, thirteen".