113020213114013 has 2 divisors, whose sum is σ = 113020213114014. Its totient is φ = 113020213114012.

The previous prime is 113020213113917. The next prime is 113020213114031. The reversal of 113020213114013 is 310411312020311.

Together with next prime (113020213114031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82522725976804 + 30497487137209 = 9084202^2 + 5522453^2 .

It is a cyclic number.

It is not a de Polignac number, because 113020213114013 - 2¹⁴ = 113020213097629 is a prime.

It is a super-2 number, since 2×113020213114013² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113020213114013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113020213114073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510106557006 + 56510106557007.

It is an arithmetic number, because the mean of its divisors is an integer number (56510106557007).

Almost surely, 2^{113020213114013} is an apocalyptic number.

It is an amenable number.

113020213114013 is a deficient number, since it is larger than the sum of its proper divisors (1).

113020213114013 is an equidigital number, since it uses as much as digits as its factorization.

113020213114013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 113020213114013 its reverse (310411312020311), we get a palindrome (423431525134324).

The spelling of 113020213114013 in words is "one hundred thirteen trillion, twenty billion, two hundred thirteen million, one hundred fourteen thousand, thirteen".