1130204023031 has 2 divisors, whose sum is σ = 1130204023032. Its totient is φ = 1130204023030.

The previous prime is 1130204022977. The next prime is 1130204023037. The reversal of 1130204023031 is 1303204020311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130204023031 is a prime.

It is a super-2 number, since 2×1130204023031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1130204022994 and 1130204023012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130204023037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565102011515 + 565102011516.

It is an arithmetic number, because the mean of its divisors is an integer number (565102011516).

Almost surely, 2^{1130204023031} is an apocalyptic number.

1130204023031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130204023031 is an equidigital number, since it uses as much as digits as its factorization.

1130204023031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1130204023031 its reverse (1303204020311), we get a palindrome (2433408043342).

The spelling of 1130204023031 in words is "one trillion, one hundred thirty billion, two hundred four million, twenty-three thousand, thirty-one".