Base | Representation |
---|---|
bin | 10000011100100101011… |
… | …011010111100000101011 |
3 | 11000001020212211201012122 |
4 | 100130211123113200223 |
5 | 122004124302030102 |
6 | 2223113025101455 |
7 | 144440342203523 |
oct | 20344533274053 |
9 | 4001225751178 |
10 | 1130204330027 |
11 | 3a6353975213 |
12 | 16305b18788b |
13 | 827685b24c6 |
14 | 3c9b8b00683 |
15 | 1e5ec4dc0a2 |
hex | 107256d782b |
1130204330027 has 2 divisors, whose sum is σ = 1130204330028. Its totient is φ = 1130204330026.
The previous prime is 1130204330023. The next prime is 1130204330041. The reversal of 1130204330027 is 7200334020311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1130204330027 - 22 = 1130204330023 is a prime.
It is a super-2 number, since 2×11302043300272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1130204329978 and 1130204330005.
It is not a weakly prime, because it can be changed into another prime (1130204330023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565102165013 + 565102165014.
It is an arithmetic number, because the mean of its divisors is an integer number (565102165014).
Almost surely, 21130204330027 is an apocalyptic number.
1130204330027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130204330027 is an equidigital number, since it uses as much as digits as its factorization.
1130204330027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 26.
Adding to 1130204330027 its reverse (7200334020311), we get a palindrome (8330538350338).
The spelling of 1130204330027 in words is "one trillion, one hundred thirty billion, two hundred four million, three hundred thirty thousand, twenty-seven".
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