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1130204330051 is a prime number
BaseRepresentation
bin10000011100100101011…
…011010111100001000011
311000001020212211201020112
4100130211123113201003
5122004124302030201
62223113025101535
7144440342203556
oct20344533274103
94001225751215
101130204330051
113a6353975235
1216305b1878ab
13827685b2514
143c9b8b0069d
151e5ec4dc0bb
hex107256d7843

1130204330051 has 2 divisors, whose sum is σ = 1130204330052. Its totient is φ = 1130204330050.

The previous prime is 1130204330041. The next prime is 1130204330063. The reversal of 1130204330051 is 1500334020311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1130204330051 - 210 = 1130204329027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130204329999 and 1130204330026.

It is not a weakly prime, because it can be changed into another prime (1130204330041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565102165025 + 565102165026.

It is an arithmetic number, because the mean of its divisors is an integer number (565102165026).

Almost surely, 21130204330051 is an apocalyptic number.

1130204330051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130204330051 is an equidigital number, since it uses as much as digits as its factorization.

1130204330051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 1130204330051 its reverse (1500334020311), we get a palindrome (2630538350362).

The spelling of 1130204330051 in words is "one trillion, one hundred thirty billion, two hundred four million, three hundred thirty thousand, fifty-one".