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1130210224453 is a prime number
BaseRepresentation
bin10000011100100101110…
…001110110100101000101
311000001021021221011211201
4100130211301312211011
5122004132304140303
62223113355302501
7144440443253452
oct20344561664505
94001237834751
101130210224453
113a6357230842
1216306114aa31
138276989742b
143c9b97d6829
151e5ecca381d
hex10725c76945

1130210224453 has 2 divisors, whose sum is σ = 1130210224454. Its totient is φ = 1130210224452.

The previous prime is 1130210224399. The next prime is 1130210224513. The reversal of 1130210224453 is 3544220120311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1124348484609 + 5861739844 = 1060353^2 + 76562^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130210224453 - 233 = 1121620289861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130210224753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565105112226 + 565105112227.

It is an arithmetic number, because the mean of its divisors is an integer number (565105112227).

Almost surely, 21130210224453 is an apocalyptic number.

It is an amenable number.

1130210224453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130210224453 is an equidigital number, since it uses as much as digits as its factorization.

1130210224453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 1130210224453 its reverse (3544220120311), we get a palindrome (4674430344764).

The spelling of 1130210224453 in words is "one trillion, one hundred thirty billion, two hundred ten million, two hundred twenty-four thousand, four hundred fifty-three".