113021400103 has 2 divisors, whose sum is σ = 113021400104. Its totient is φ = 113021400102.

The previous prime is 113021400077. The next prime is 113021400113. The reversal of 113021400103 is 301004120311.

It is a strong prime.

It is an emirp because it is prime and its reverse (301004120311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113021400103 - 2⁵ = 113021400071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113021400113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510700051 + 56510700052.

It is an arithmetic number, because the mean of its divisors is an integer number (56510700052).

Almost surely, 2^113021400103 is an apocalyptic number.

113021400103 is a deficient number, since it is larger than the sum of its proper divisors (1).

113021400103 is an equidigital number, since it uses as much as digits as its factorization.

113021400103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 113021400103 its reverse (301004120311), we get a palindrome (414025520414).

The spelling of 113021400103 in words is "one hundred thirteen billion, twenty-one million, four hundred thousand, one hundred three".