Base | Representation |
---|---|
bin | 110100101000010011… |
… | …0100001001100110001 |
3 | 101210201122202020111201 |
4 | 1221100212201030301 |
5 | 3322431441040213 |
6 | 123531001211201 |
7 | 11110530154021 |
oct | 1512046411461 |
9 | 353648666451 |
10 | 113021424433 |
11 | 43a28713aa5 |
12 | 19aa2790b01 |
13 | a872473008 |
14 | 56825a5a81 |
15 | 2e174be6dd |
hex | 1a509a1331 |
113021424433 has 2 divisors, whose sum is σ = 113021424434. Its totient is φ = 113021424432.
The previous prime is 113021424419. The next prime is 113021424463. The reversal of 113021424433 is 334424120311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96915783969 + 16105640464 = 311313^2 + 126908^2 .
It is a cyclic number.
It is not a de Polignac number, because 113021424433 - 217 = 113021293361 is a prime.
It is not a weakly prime, because it can be changed into another prime (113021424463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510712216 + 56510712217.
It is an arithmetic number, because the mean of its divisors is an integer number (56510712217).
Almost surely, 2113021424433 is an apocalyptic number.
It is an amenable number.
113021424433 is a deficient number, since it is larger than the sum of its proper divisors (1).
113021424433 is an equidigital number, since it uses as much as digits as its factorization.
113021424433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 113021424433 its reverse (334424120311), we get a palindrome (447445544744).
The spelling of 113021424433 in words is "one hundred thirteen billion, twenty-one million, four hundred twenty-four thousand, four hundred thirty-three".
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