Base | Representation |
---|---|
bin | 110100101000010100… |
… | …0101101101101010101 |
3 | 101210201200211110222102 |
4 | 1221100220231231111 |
5 | 3322432112444312 |
6 | 123531021411445 |
7 | 11110535101646 |
oct | 1512050555525 |
9 | 353650743872 |
10 | 113021999957 |
11 | 43a28a77439 |
12 | 19aa2a09b85 |
13 | a872614c69 |
14 | 56826b56cd |
15 | 2e17584ec2 |
hex | 1a50a2db55 |
113021999957 has 2 divisors, whose sum is σ = 113021999958. Its totient is φ = 113021999956.
The previous prime is 113021999953. The next prime is 113022000019. The reversal of 113021999957 is 759999120311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67551128836 + 45470871121 = 259906^2 + 213239^2 .
It is a cyclic number.
It is not a de Polignac number, because 113021999957 - 22 = 113021999953 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113021999953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510999978 + 56510999979.
It is an arithmetic number, because the mean of its divisors is an integer number (56510999979).
Almost surely, 2113021999957 is an apocalyptic number.
It is an amenable number.
113021999957 is a deficient number, since it is larger than the sum of its proper divisors (1).
113021999957 is an equidigital number, since it uses as much as digits as its factorization.
113021999957 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1377810, while the sum is 56.
The spelling of 113021999957 in words is "one hundred thirteen billion, twenty-one million, nine hundred ninety-nine thousand, nine hundred fifty-seven".
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