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11302260491 is a prime number
BaseRepresentation
bin10101000011010101…
…01100111100001011
31002011200012022200102
422201222230330023
5141121334313431
65105302400015
7550036425524
oct124152547413
932150168612
1011302260491
11487a916655
12223513000b
1310b1737302
147930b184b
15462397dcb
hex2a1aacf0b

11302260491 has 2 divisors, whose sum is σ = 11302260492. Its totient is φ = 11302260490.

The previous prime is 11302260443. The next prime is 11302260493. The reversal of 11302260491 is 19406220311.

11302260491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11302260491 - 26 = 11302260427 is a prime.

It is a super-2 number, since 2×113022604912 (a number of 21 digits) contains 22 as substring.

Together with 11302260493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11302260493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651130245 + 5651130246.

It is an arithmetic number, because the mean of its divisors is an integer number (5651130246).

Almost surely, 211302260491 is an apocalyptic number.

11302260491 is a deficient number, since it is larger than the sum of its proper divisors (1).

11302260491 is an equidigital number, since it uses as much as digits as its factorization.

11302260491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 11302260491 in words is "eleven billion, three hundred two million, two hundred sixty thousand, four hundred ninety-one".