Base | Representation |
---|---|
bin | 10000011100100111000… |
… | …010101111111111010011 |
3 | 11000001022202211120220221 |
4 | 100130213002233333103 |
5 | 122004203221243443 |
6 | 2223115434013511 |
7 | 144441121436464 |
oct | 20344702577723 |
9 | 4001282746827 |
10 | 1130231431123 |
11 | 3a63681a5713 |
12 | 163068277297 |
13 | 827710b0b62 |
14 | 3c9bc556d6b |
15 | 1e5eea91eed |
hex | 107270affd3 |
1130231431123 has 2 divisors, whose sum is σ = 1130231431124. Its totient is φ = 1130231431122.
The previous prime is 1130231431103. The next prime is 1130231431171. The reversal of 1130231431123 is 3211341320311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1130231431123 - 221 = 1130229333971 is a prime.
It is a super-2 number, since 2×11302314311232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1130231431103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565115715561 + 565115715562.
It is an arithmetic number, because the mean of its divisors is an integer number (565115715562).
Almost surely, 21130231431123 is an apocalyptic number.
1130231431123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130231431123 is an equidigital number, since it uses as much as digits as its factorization.
1130231431123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1130231431123 its reverse (3211341320311), we get a palindrome (4341572751434).
The spelling of 1130231431123 in words is "one trillion, one hundred thirty billion, two hundred thirty-one million, four hundred thirty-one thousand, one hundred twenty-three".
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