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1130231431123 is a prime number
BaseRepresentation
bin10000011100100111000…
…010101111111111010011
311000001022202211120220221
4100130213002233333103
5122004203221243443
62223115434013511
7144441121436464
oct20344702577723
94001282746827
101130231431123
113a63681a5713
12163068277297
13827710b0b62
143c9bc556d6b
151e5eea91eed
hex107270affd3

1130231431123 has 2 divisors, whose sum is σ = 1130231431124. Its totient is φ = 1130231431122.

The previous prime is 1130231431103. The next prime is 1130231431171. The reversal of 1130231431123 is 3211341320311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1130231431123 - 221 = 1130229333971 is a prime.

It is a super-2 number, since 2×11302314311232 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1130231431103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565115715561 + 565115715562.

It is an arithmetic number, because the mean of its divisors is an integer number (565115715562).

Almost surely, 21130231431123 is an apocalyptic number.

1130231431123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130231431123 is an equidigital number, since it uses as much as digits as its factorization.

1130231431123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1130231431123 its reverse (3211341320311), we get a palindrome (4341572751434).

The spelling of 1130231431123 in words is "one trillion, one hundred thirty billion, two hundred thirty-one million, four hundred thirty-one thousand, one hundred twenty-three".