Base | Representation |
---|---|
bin | 110100101000011000… |
… | …1111111001110111001 |
3 | 101210201212101222210021 |
4 | 1221100301333032321 |
5 | 3322433223243113 |
6 | 123531145450441 |
7 | 11110564545433 |
oct | 1512061771671 |
9 | 353655358707 |
10 | 113024431033 |
11 | 43a2a387998 |
12 | 19aa37a0a21 |
13 | a872c86677 |
14 | 5682b49653 |
15 | 2e178b548d |
hex | 1a50c7f3b9 |
113024431033 has 2 divisors, whose sum is σ = 113024431034. Its totient is φ = 113024431032.
The previous prime is 113024431007. The next prime is 113024431067. The reversal of 113024431033 is 330134420311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75708623104 + 37315807929 = 275152^2 + 193173^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113024431033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113024430989 and 113024431007.
It is not a weakly prime, because it can be changed into another prime (113024437033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56512215516 + 56512215517.
It is an arithmetic number, because the mean of its divisors is an integer number (56512215517).
Almost surely, 2113024431033 is an apocalyptic number.
It is an amenable number.
113024431033 is a deficient number, since it is larger than the sum of its proper divisors (1).
113024431033 is an equidigital number, since it uses as much as digits as its factorization.
113024431033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 113024431033 its reverse (330134420311), we get a palindrome (443158851344).
The spelling of 113024431033 in words is "one hundred thirteen billion, twenty-four million, four hundred thirty-one thousand, thirty-three".
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