Base | Representation |
---|---|
bin | 10000011100100111110… |
… | …011111000110100010111 |
3 | 11000001100200002000122011 |
4 | 100130213303320310113 |
5 | 122004220020443333 |
6 | 2223121014045051 |
7 | 144441336066166 |
oct | 20344763706427 |
9 | 4001320060564 |
10 | 1130244312343 |
11 | 3a63744a3553 |
12 | 163070649787 |
13 | 82773970c93 |
14 | 3c9c014b3dd |
15 | 1e600c889cd |
hex | 10727cf8d17 |
1130244312343 has 2 divisors, whose sum is σ = 1130244312344. Its totient is φ = 1130244312342.
The previous prime is 1130244312331. The next prime is 1130244312359. The reversal of 1130244312343 is 3432134420311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1130244312343 - 217 = 1130244181271 is a prime.
It is a super-4 number, since 4×11302443123434 (a number of 49 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130244312143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565122156171 + 565122156172.
It is an arithmetic number, because the mean of its divisors is an integer number (565122156172).
Almost surely, 21130244312343 is an apocalyptic number.
1130244312343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130244312343 is an equidigital number, since it uses as much as digits as its factorization.
1130244312343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 1130244312343 its reverse (3432134420311), we get a palindrome (4562378732654).
The spelling of 1130244312343 in words is "one trillion, one hundred thirty billion, two hundred forty-four million, three hundred twelve thousand, three hundred forty-three".
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