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11302443241 is a prime number
BaseRepresentation
bin10101000011010110…
…11001100011101001
31002011200112121100221
422201223121203221
5141121411140431
65105310330041
7550041116365
oct124153314351
932150477327
1011302443241
11487aa30991
1222351b9921
1310b179c54b
1479311c2a5
154623d2111
hex2a1ad98e9

11302443241 has 2 divisors, whose sum is σ = 11302443242. Its totient is φ = 11302443240.

The previous prime is 11302443223. The next prime is 11302443247. The reversal of 11302443241 is 14234420311.

11302443241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11229852841 + 72590400 = 105971^2 + 8520^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11302443241 is a prime.

It is not a weakly prime, because it can be changed into another prime (11302443247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651221620 + 5651221621.

It is an arithmetic number, because the mean of its divisors is an integer number (5651221621).

Almost surely, 211302443241 is an apocalyptic number.

It is an amenable number.

11302443241 is a deficient number, since it is larger than the sum of its proper divisors (1).

11302443241 is an equidigital number, since it uses as much as digits as its factorization.

11302443241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 11302443241 its reverse (14234420311), we get a palindrome (25536863552).

The spelling of 11302443241 in words is "eleven billion, three hundred two million, four hundred forty-three thousand, two hundred forty-one".