Base | Representation |
---|---|
bin | 10000011100101000011… |
… | …010000001111010011111 |
3 | 11000001101100220000022102 |
4 | 100130220122001322133 |
5 | 122004230100423241 |
6 | 2223122012235315 |
7 | 144441520062044 |
oct | 20345032017237 |
9 | 4001340800272 |
10 | 1130254311071 |
11 | 3a637a102766 |
12 | 163073a6bb3b |
13 | 82775a620a2 |
14 | 3c9c15d11cb |
15 | 1e601ab139b |
hex | 10728681e9f |
1130254311071 has 2 divisors, whose sum is σ = 1130254311072. Its totient is φ = 1130254311070.
The previous prime is 1130254311001. The next prime is 1130254311077. The reversal of 1130254311071 is 1701134520311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1130254311071 - 210 = 1130254310047 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130254311077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565127155535 + 565127155536.
It is an arithmetic number, because the mean of its divisors is an integer number (565127155536).
Almost surely, 21130254311071 is an apocalyptic number.
1130254311071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130254311071 is an equidigital number, since it uses as much as digits as its factorization.
1130254311071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 29.
Adding to 1130254311071 its reverse (1701134520311), we get a palindrome (2831388831382).
The spelling of 1130254311071 in words is "one trillion, one hundred thirty billion, two hundred fifty-four million, three hundred eleven thousand, seventy-one".
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