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1130301301312 = 2617660957833
BaseRepresentation
bin10000011100101011001…
…101010010001001000000
311000001111122022100210201
4100130223031102021000
5122004324113120222
62223130411334544
7144442630352611
oct20345315221100
94001448270721
101130301301312
113a63a3688177
12163087751454
1382782705571
143c9c7943c08
151e605c94427
hex1072b352240

1130301301312 has 14 divisors (see below), whose sum is σ = 2242941644918. Its totient is φ = 565150650624.

The previous prime is 1130301301247. The next prime is 1130301301357. The reversal of 1130301301312 is 2131031030311.

It can be written as a sum of positive squares in only one way, i.e., 1128897750016 + 1403551296 = 1062496^2 + 37464^2 .

It is a super-2 number, since 2×11303013013122 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1130301301312.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8830478853 + ... + 8830478980.

Almost surely, 21130301301312 is an apocalyptic number.

It is an amenable number.

1130301301312 is a deficient number, since it is larger than the sum of its proper divisors (1112640343606).

1130301301312 is an equidigital number, since it uses as much as digits as its factorization.

1130301301312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17660957845 (or 17660957835 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1130301301312 its reverse (2131031030311), we get a palindrome (3261332331623).

The spelling of 1130301301312 in words is "one trillion, one hundred thirty billion, three hundred one million, three hundred one thousand, three hundred twelve".

Divisors: 1 2 4 8 16 32 64 17660957833 35321915666 70643831332 141287662664 282575325328 565150650656 1130301301312