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113030201423 is a prime number
BaseRepresentation
bin110100101000100100…
…0000000000001001111
3101210202021021011021102
41221101020000001033
53322441212421143
6123531513253315
711110664600636
oct1512110000117
9353667234242
10113030201423
1143a32669307
1219aa570423b
13a874226cb9
14568380c51d
152e181550b8
hex1a5120004f

113030201423 has 2 divisors, whose sum is σ = 113030201424. Its totient is φ = 113030201422.

The previous prime is 113030201413. The next prime is 113030201489. The reversal of 113030201423 is 324102030311.

It is a weak prime.

It is an emirp because it is prime and its reverse (324102030311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113030201423 - 222 = 113026007119 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 113030201395 and 113030201404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113030201413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56515100711 + 56515100712.

It is an arithmetic number, because the mean of its divisors is an integer number (56515100712).

Almost surely, 2113030201423 is an apocalyptic number.

113030201423 is a deficient number, since it is larger than the sum of its proper divisors (1).

113030201423 is an equidigital number, since it uses as much as digits as its factorization.

113030201423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 113030201423 its reverse (324102030311), we get a palindrome (437132231734).

The spelling of 113030201423 in words is "one hundred thirteen billion, thirty million, two hundred one thousand, four hundred twenty-three".