Search a number
-
+
1130302102120 = 23573463836047
BaseRepresentation
bin10000011100101011010…
…000010101101001101000
311000001111200211001022021
4100130223100111221220
5122004324314231440
62223130440434224
7144442640226412
oct20345320255150
94001450731267
101130302102120
113a63a40848a4
12163087a78974
1382782925c09
143c9c7ab19b2
151e605da184a
hex1072b415a68

1130302102120 has 64 divisors (see below), whose sum is σ = 2583588971520. Its totient is φ = 444963746304.

The previous prime is 1130302102109. The next prime is 1130302102129. The reversal of 1130302102120 is 212012030311.

It is a junction number, because it is equal to n+sod(n) for n = 1130302102094 and 1130302102103.

It is not an unprimeable number, because it can be changed into a prime (1130302102129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 933937 + ... + 1769983.

It is an arithmetic number, because the mean of its divisors is an integer number (40368577680).

Almost surely, 21130302102120 is an apocalyptic number.

1130302102120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1130302102120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1291794485760).

1130302102120 is an abundant number, since it is smaller than the sum of its proper divisors (1453286869400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1130302102120 is a wasteful number, since it uses less digits than its factorization.

1130302102120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 836594 (or 836590 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1130302102120 its reverse (212012030311), we get a palindrome (1342314132431).

The spelling of 1130302102120 in words is "one trillion, one hundred thirty billion, three hundred two million, one hundred two thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 20 40 73 146 292 365 463 584 730 926 1460 1852 2315 2920 3704 4630 9260 18520 33799 67598 135196 168995 270392 337990 675980 836047 1351960 1672094 3344188 4180235 6688376 8360470 16720940 33441880 61031431 122062862 244125724 305157155 387089761 488251448 610314310 774179522 1220628620 1548359044 1935448805 2441257240 3096718088 3870897610 7741795220 15483590440 28257552553 56515105106 113030210212 141287762765 226060420424 282575525530 565151051060 1130302102120