Base | Representation |
---|---|
bin | 10000011100101011010… |
… | …000010111100110011011 |
3 | 11000001111200211110021002 |
4 | 100130223100113212123 |
5 | 122004324320010412 |
6 | 2223130440535215 |
7 | 144442640261612 |
oct | 20345320274633 |
9 | 4001450743232 |
10 | 1130302110107 |
11 | 3a63a408a8a5 |
12 | 163087a8150b |
13 | 82782929741 |
14 | 3c9c7ab4879 |
15 | 1e605da3dc2 |
hex | 1072b41799b |
1130302110107 has 2 divisors, whose sum is σ = 1130302110108. Its totient is φ = 1130302110106.
The previous prime is 1130302109957. The next prime is 1130302110127. The reversal of 1130302110107 is 7010112030311.
It is an a-pointer prime, because the next prime (1130302110127) can be obtained adding 1130302110107 to its sum of digits (20).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130302110107 is a prime.
It is a super-2 number, since 2×11303021101072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1130302110127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565151055053 + 565151055054.
It is an arithmetic number, because the mean of its divisors is an integer number (565151055054).
Almost surely, 21130302110107 is an apocalyptic number.
1130302110107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130302110107 is an equidigital number, since it uses as much as digits as its factorization.
1130302110107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 1130302110107 its reverse (7010112030311), we get a palindrome (8140414140418).
The spelling of 1130302110107 in words is "one trillion, one hundred thirty billion, three hundred two million, one hundred ten thousand, one hundred seven".
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