Base | Representation |
---|---|
bin | 10101000011011011… |
… | …11010111111001001 |
3 | 1002011201210012101102 |
4 | 22201231322333021 |
5 | 141122043320312 |
6 | 5105332431145 |
7 | 550046542211 |
oct | 124155727711 |
9 | 32151705342 |
10 | 11303104457 |
11 | 4880342747 |
12 | 22354784b5 |
13 | 10b19714b8 |
14 | 793251241 |
15 | 4624b2ec2 |
hex | 2a1b7afc9 |
11303104457 has 2 divisors, whose sum is σ = 11303104458. Its totient is φ = 11303104456.
The previous prime is 11303104403. The next prime is 11303104459. The reversal of 11303104457 is 75440130311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10425226816 + 877877641 = 102104^2 + 29629^2 .
It is a cyclic number.
It is not a de Polignac number, because 11303104457 - 214 = 11303088073 is a prime.
Together with 11303104459, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11303104459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651552228 + 5651552229.
It is an arithmetic number, because the mean of its divisors is an integer number (5651552229).
Almost surely, 211303104457 is an apocalyptic number.
It is an amenable number.
11303104457 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303104457 is an equidigital number, since it uses as much as digits as its factorization.
11303104457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 11303104457 its reverse (75440130311), we get a palindrome (86743234768).
The spelling of 11303104457 in words is "eleven billion, three hundred three million, one hundred four thousand, four hundred fifty-seven".
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