1130311102130 has 64 divisors (see below), whose sum is σ = 2364752931840. Its totient is φ = 380987103744.

The previous prime is 1130311102121. The next prime is 1130311102267. The reversal of 1130311102130 is 312011130311.

It is a junction number, because it is equal to n+sod(n) for n = 1130311102099 and 1130311102108.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 849872 + ... + 1727108.

It is an arithmetic number, because the mean of its divisors is an integer number (36949264560).

Almost surely, 2^{1130311102130} is an apocalyptic number.

1130311102130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1130311102130 is an abundant number, since it is smaller than the sum of its proper divisors (1234441829710).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1130311102130 is a wasteful number, since it uses less digits than its factorization.

1130311102130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 877563.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1130311102130 its reverse (312011130311), we get a palindrome (1442322232441).

The spelling of 1130311102130 in words is "one trillion, one hundred thirty billion, three hundred eleven million, one hundred two thousand, one hundred thirty".