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113031213233 is a prime number
BaseRepresentation
bin110100101000100101…
…1110111000010110001
3101210202100011120012212
41221101023313002301
53322441442310413
6123531551101505
711111006313551
oct1512113670261
9353670146185
10113031213233
1143a3319a514
1219aa5b11895
13a8744bc6c3
1456839d3161
152e182a4ca8
hex1a512f70b1

113031213233 has 2 divisors, whose sum is σ = 113031213234. Its totient is φ = 113031213232.

The previous prime is 113031213209. The next prime is 113031213293. The reversal of 113031213233 is 332312130311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86661350689 + 26369862544 = 294383^2 + 162388^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113031213233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113031213199 and 113031213208.

It is not a weakly prime, because it can be changed into another prime (113031213293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56515606616 + 56515606617.

It is an arithmetic number, because the mean of its divisors is an integer number (56515606617).

Almost surely, 2113031213233 is an apocalyptic number.

It is an amenable number.

113031213233 is a deficient number, since it is larger than the sum of its proper divisors (1).

113031213233 is an equidigital number, since it uses as much as digits as its factorization.

113031213233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 113031213233 its reverse (332312130311), we get a palindrome (445343343544).

The spelling of 113031213233 in words is "one hundred thirteen billion, thirty-one million, two hundred thirteen thousand, two hundred thirty-three".