11303131101120 has 672 divisors, whose sum is σ = 40637040814656. Its totient is φ = 2881142784000.

The previous prime is 11303131101077. The next prime is 11303131101137. The reversal of 11303131101120 is 2110113130311.

11303131101120 is a `hidden beast` number, since 1 + 130 + 313 + 1 + 101 + 120 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 11303131101093 and 11303131101102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1409891352 + ... + 1409899368.

Almost surely, 2^{11303131101120} is an apocalyptic number.

11303131101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11303131101120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20318520407328).

11303131101120 is an abundant number, since it is smaller than the sum of its proper divisors (29333909713536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11303131101120 is a wasteful number, since it uses less digits than its factorization.

11303131101120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8309 (or 8296 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 11303131101120 its reverse (2110113130311), we get a palindrome (13413244231431).

The spelling of 11303131101120 in words is "eleven trillion, three hundred three billion, one hundred thirty-one million, one hundred one thousand, one hundred twenty".