Base | Representation |
---|---|
bin | 1010010001111011101101… |
… | …1010110011101000100111 |
3 | 1111000120112200012100022011 |
4 | 2210132323122303220213 |
5 | 2440142430022304112 |
6 | 40012341523015051 |
7 | 2244425625664243 |
oct | 244367332635047 |
9 | 44016480170264 |
10 | 11303203322407 |
11 | 36687306687a7 |
12 | 1326777b0a487 |
13 | 63cb6cab57b9 |
14 | 2b1113cc9423 |
15 | 1490501c0aa7 |
hex | a47bb6b3a27 |
11303203322407 has 2 divisors, whose sum is σ = 11303203322408. Its totient is φ = 11303203322406.
The previous prime is 11303203322273. The next prime is 11303203322423. The reversal of 11303203322407 is 70422330230311.
It is a strong prime.
It is an emirp because it is prime and its reverse (70422330230311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11303203322407 is a prime.
It is a super-3 number, since 3×113032033224073 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11303203322447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651601661203 + 5651601661204.
It is an arithmetic number, because the mean of its divisors is an integer number (5651601661204).
Almost surely, 211303203322407 is an apocalyptic number.
11303203322407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303203322407 is an equidigital number, since it uses as much as digits as its factorization.
11303203322407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 11303203322407 its reverse (70422330230311), we get a palindrome (81725533552718).
The spelling of 11303203322407 in words is "eleven trillion, three hundred three billion, two hundred three million, three hundred twenty-two thousand, four hundred seven".
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