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1130323214341 is a prime number
BaseRepresentation
bin10000011100101100100…
…000111000000000000101
311000001120011112122211101
4100130230200320000011
5122004400220324331
62223132513140101
7144443314540156
oct20345440700005
94001504478741
101130323214341
113a6404a94812
12163092b5a631
1382787108659
143c9ca80992d
151e607b72061
hex1072c838005

1130323214341 has 2 divisors, whose sum is σ = 1130323214342. Its totient is φ = 1130323214340.

The previous prime is 1130323214281. The next prime is 1130323214411. The reversal of 1130323214341 is 1434123230311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1074321885025 + 56001329316 = 1036495^2 + 236646^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130323214341 - 27 = 1130323214213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130323214441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565161607170 + 565161607171.

It is an arithmetic number, because the mean of its divisors is an integer number (565161607171).

Almost surely, 21130323214341 is an apocalyptic number.

It is an amenable number.

1130323214341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130323214341 is an equidigital number, since it uses as much as digits as its factorization.

1130323214341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1130323214341 its reverse (1434123230311), we get a palindrome (2564446444652).

The spelling of 1130323214341 in words is "one trillion, one hundred thirty billion, three hundred twenty-three million, two hundred fourteen thousand, three hundred forty-one".