Base | Representation |
---|---|
bin | 10101000011011111… |
… | …00001100010001101 |
3 | 1002011202120112120022 |
4 | 22201233201202031 |
5 | 141122200240433 |
6 | 5105345431525 |
7 | 550053241622 |
oct | 124157414215 |
9 | 32152515508 |
10 | 11303524493 |
11 | 48805aa288 |
12 | 223563b5a5 |
13 | 10b1a8a741 |
14 | 793320349 |
15 | 462547698 |
hex | 2a1be188d |
11303524493 has 2 divisors, whose sum is σ = 11303524494. Its totient is φ = 11303524492.
The previous prime is 11303524459. The next prime is 11303524523. The reversal of 11303524493 is 39442530311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7718149609 + 3585374884 = 87853^2 + 59878^2 .
It is an emirp because it is prime and its reverse (39442530311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11303524493 - 232 = 7008557197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11303524433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651762246 + 5651762247.
It is an arithmetic number, because the mean of its divisors is an integer number (5651762247).
Almost surely, 211303524493 is an apocalyptic number.
It is an amenable number.
11303524493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303524493 is an equidigital number, since it uses as much as digits as its factorization.
11303524493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 11303524493 in words is "eleven billion, three hundred three million, five hundred twenty-four thousand, four hundred ninety-three".
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