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11303524493 is a prime number
BaseRepresentation
bin10101000011011111…
…00001100010001101
31002011202120112120022
422201233201202031
5141122200240433
65105345431525
7550053241622
oct124157414215
932152515508
1011303524493
1148805aa288
12223563b5a5
1310b1a8a741
14793320349
15462547698
hex2a1be188d

11303524493 has 2 divisors, whose sum is σ = 11303524494. Its totient is φ = 11303524492.

The previous prime is 11303524459. The next prime is 11303524523. The reversal of 11303524493 is 39442530311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7718149609 + 3585374884 = 87853^2 + 59878^2 .

It is an emirp because it is prime and its reverse (39442530311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11303524493 - 232 = 7008557197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11303524433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651762246 + 5651762247.

It is an arithmetic number, because the mean of its divisors is an integer number (5651762247).

Almost surely, 211303524493 is an apocalyptic number.

It is an amenable number.

11303524493 is a deficient number, since it is larger than the sum of its proper divisors (1).

11303524493 is an equidigital number, since it uses as much as digits as its factorization.

11303524493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

The spelling of 11303524493 in words is "eleven billion, three hundred three million, five hundred twenty-four thousand, four hundred ninety-three".