Base | Representation |
---|---|
bin | 1101011110011… |
… | …10010000101101 |
3 | 21212201011010102 |
4 | 12233032100231 |
5 | 212414324402 |
6 | 15114520445 |
7 | 2541562622 |
oct | 657162055 |
9 | 255634112 |
10 | 113042477 |
11 | 5889a539 |
12 | 31a36125 |
13 | 1a55c152 |
14 | 11028349 |
15 | 9dce102 |
hex | 6bce42d |
113042477 has 2 divisors, whose sum is σ = 113042478. Its totient is φ = 113042476.
The previous prime is 113042441. The next prime is 113042507. The reversal of 113042477 is 774240311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87347716 + 25694761 = 9346^2 + 5069^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113042477 is a prime.
It is a super-3 number, since 3×1130424773 (a number of 25 digits) contains 333 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113042977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56521238 + 56521239.
It is an arithmetic number, because the mean of its divisors is an integer number (56521239).
Almost surely, 2113042477 is an apocalyptic number.
It is an amenable number.
113042477 is a deficient number, since it is larger than the sum of its proper divisors (1).
113042477 is an equidigital number, since it uses as much as digits as its factorization.
113042477 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4704, while the sum is 29.
The square root of 113042477 is about 10632.1435750276. The cubic root of 113042477 is about 483.5193829394.
Adding to 113042477 its reverse (774240311), we get a palindrome (887282788).
The spelling of 113042477 in words is "one hundred thirteen million, forty-two thousand, four hundred seventy-seven".
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