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11304340013144 = 231413042501643
BaseRepresentation
bin1010010001111111111100…
…1010111100000001011000
31111000200110220002012212002
42210133333022330001120
52440202242020410034
640013050410140132
72244466040463353
oct244377712740130
944020426065762
1011304340013144
113669164263332
121326a34721648
1363ccc1441979
142b11c0c5929a
151490b9da2e7e
hexa47ff2bc058

11304340013144 has 8 divisors (see below), whose sum is σ = 21195637524660. Its totient is φ = 5652170006568.

The previous prime is 11304340013051. The next prime is 11304340013171. The reversal of 11304340013144 is 44131004340311.

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-3 number, since 3×113043400131443 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706521250814 + ... + 706521250829.

Almost surely, 211304340013144 is an apocalyptic number.

It is an amenable number.

11304340013144 is a deficient number, since it is larger than the sum of its proper divisors (9891297511516).

11304340013144 is a wasteful number, since it uses less digits than its factorization.

11304340013144 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1413042501649 (or 1413042501645 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11304340013144 its reverse (44131004340311), we get a palindrome (55435344353455).

The spelling of 11304340013144 in words is "eleven trillion, three hundred four billion, three hundred forty million, thirteen thousand, one hundred forty-four".

Divisors: 1 2 4 8 1413042501643 2826085003286 5652170006572 11304340013144