11304431113403 has 2 divisors, whose sum is σ = 11304431113404. Its totient is φ = 11304431113402.

The previous prime is 11304431113379. The next prime is 11304431113427. The reversal of 11304431113403 is 30431113440311.

It is a balanced prime because it is at equal distance from previous prime (11304431113379) and next prime (11304431113427).

It is an emirp because it is prime and its reverse (30431113440311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11304431113403 - 2¹⁰ = 11304431112379 is a prime.

It is a super-3 number, since 3×11304431113403³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11304431113453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652215556701 + 5652215556702.

It is an arithmetic number, because the mean of its divisors is an integer number (5652215556702).

Almost surely, 2^{11304431113403} is an apocalyptic number.

11304431113403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304431113403 is an equidigital number, since it uses as much as digits as its factorization.

11304431113403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 11304431113403 its reverse (30431113440311), we get a palindrome (41735544553714).

The spelling of 11304431113403 in words is "eleven trillion, three hundred four billion, four hundred thirty-one million, one hundred thirteen thousand, four hundred three".