113044315541 has 4 divisors (see below), whose sum is σ = 115449513792. Its totient is φ = 110639117292.

The previous prime is 113044315529. The next prime is 113044315583. The reversal of 113044315541 is 145513440311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 145513440311 = 80231 ⋅1813681.

It is a cyclic number.

It is not a de Polignac number, because 113044315541 - 2²² = 113040121237 is a prime.

It is a super-3 number, since 3×113044315541³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113044315498 and 113044315507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113044315441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1202599055 + ... + 1202599148.

It is an arithmetic number, because the mean of its divisors is an integer number (28862378448).

Almost surely, 2^113044315541 is an apocalyptic number.

It is an amenable number.

113044315541 is a deficient number, since it is larger than the sum of its proper divisors (2405198251).

113044315541 is an equidigital number, since it uses as much as digits as its factorization.

113044315541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2405198250.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 113044315541 its reverse (145513440311), we get a palindrome (258557755852).

The spelling of 113044315541 in words is "one hundred thirteen billion, forty-four million, three hundred fifteen thousand, five hundred forty-one".