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113044330453 is a prime number
BaseRepresentation
bin110100101000111110…
…1111001011111010101
3101210210020211222122211
41221101331321133111
53323003322033303
6123533140153421
711111225645305
oct1512175713725
9353706758584
10113044330453
1143a3a63969a
1219aaa398871
13a877133082
145685649605
152e194e666d
hex1a51f797d5

113044330453 has 2 divisors, whose sum is σ = 113044330454. Its totient is φ = 113044330452.

The previous prime is 113044330409. The next prime is 113044330489. The reversal of 113044330453 is 354033440311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91142402404 + 21901928049 = 301898^2 + 147993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113044330453 is a prime.

It is a super-3 number, since 3×1130443304533 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113044336453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56522165226 + 56522165227.

It is an arithmetic number, because the mean of its divisors is an integer number (56522165227).

Almost surely, 2113044330453 is an apocalyptic number.

It is an amenable number.

113044330453 is a deficient number, since it is larger than the sum of its proper divisors (1).

113044330453 is an equidigital number, since it uses as much as digits as its factorization.

113044330453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 113044330453 its reverse (354033440311), we get a palindrome (467077770764).

The spelling of 113044330453 in words is "one hundred thirteen billion, forty-four million, three hundred thirty thousand, four hundred fifty-three".